Find the exact solutions of the given equation in the interval [0,2π). sin 2x = sin x

A) $x = \frac { 2 \pi } { 3 } , \pi , \frac { 4 \pi } { 3 }$
B) $x = 0 , \frac { \pi } { 3 } , \pi , \frac { 5 \pi } { 3 }$
C) $x = \frac { \pi } { 2 } , \frac { 7 \pi } { 6 } , \frac { 11 \pi } { 6 }$
D) $x = 0 , \frac { \pi } { 3 } , \frac { 2 \pi } { 3 } , \pi , \frac { 4 \pi } { 3 } , \frac { 5 \pi } { 3 }$
E) $x = 0$

Question

Find the exact solutions of the given equation in the interval [0,2π). sin 2x = sin x
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A) $x = \frac { 2 \pi } { 3 } , \pi , \frac { 4 \pi } { 3 }$
B) $x = 0 , \frac { \pi } { 3 } , \pi , \frac { 5 \pi } { 3 }$
C) $x = \frac { \pi } { 2 } , \frac { 7 \pi } { 6 } , \frac { 11 \pi } { 6 }$
D) $x = 0 , \frac { \pi } { 3 } , \frac { 2 \pi } { 3 } , \pi , \frac { 4 \pi } { 3 } , \frac { 5 \pi } { 3 }$
E) $x = 0$

Quizplus · Accepted Answer

The Answer of Find the exact solutions of the given equation in the interval [0,2π). sin 2x = sin x
​
A) $x = \frac { 2 \pi } { 3 } , \pi , \frac { 4 \pi } { 3 }$
B) $x = 0 , \frac { \pi } { 3 } , \pi , \frac { 5 \pi } { 3 }$
C) $x = \frac { \pi } { 2 } , \frac { 7 \pi } { 6 } , \frac { 11 \pi } { 6 }$
D) $x = 0 , \frac { \pi } { 3 } , \frac { 2 \pi } { 3 } , \pi , \frac { 4 \pi } { 3 } , \frac { 5 \pi } { 3 }$
E) $x = 0$

Find the Exact Solutions of the Given Equation in the Interval