Find the expression as the tangent of an angle. $$\frac { \tan 130 ^ { \circ } - \tan 30 ^ { \circ } } { 1 + \tan 130 ^ { \circ } \tan 30 ^ { \circ } }$$
A) $\tan ^ { - 1 } 100 ^ { \circ }$
B) $\tan ^ { - 1 } 130 ^ { \circ }$
C) $\tan 160 ^ { \circ }$
D) $\tan 100 ^ { \circ }$
E) $\tan 30 ^ { \circ }$

Question

Find the expression as the tangent of an angle.​ $$\frac { \tan 130 ^ { \circ } - \tan 30 ^ { \circ } } { 1 + \tan 130 ^ { \circ } \tan 30 ^ { \circ } }$$ ​
A) $\tan ^ { - 1 } 100 ^ { \circ }$
B) $\tan ^ { - 1 } 130 ^ { \circ }$
C) $\tan 160 ^ { \circ }$
D) $\tan 100 ^ { \circ }$
E) $\tan 30 ^ { \circ }$

Quizplus · Accepted Answer

The given expression can be written as $-\dfrac{1}{\sqrt{3}}$. This is the negative reciprocal of $\sqrt{3}/1$, so it can be expressed as $	an	heta$ where $	heta$ is a $30^\circ$ angle in the second quadrant. Therefore, the answer is $\boxed{	extbf{(D)}\ 11ea99db_b44c_2d11_94ac_8b535629ba9b_TB4590_11}$.

Find the Expression as the Tangent of an Angle tan⁡130∘−tan⁡30∘1+tan⁡130∘tan⁡30∘\frac { \tan 130 ^ { \circ } - \tan 30 ^ { \circ } } { 1 + \tan 130 ^ { \circ } \tan 30 ^ { \circ } }1+tan130∘tan30∘tan130∘−tan30∘​

Find the Expression as the Tangent of an Angle $\frac { \tan 130 ^ { \circ } - \tan 30 ^ { \circ } } { 1 + \tan 130 ^ { \circ } \tan 30 ^ { \circ } }$