Find the dimensions of the rectangle meeting the specified condition.
The perimeter is 528 feet and the length is $$4 \frac { 1 } { 2 }$$ times the width.

A)216 ft × 52 ft
B)216 ft × 48 ft
C)220 ft × 52 ft
D)218 ft × 48 ft
E)218 ft × 50 ft

Question

Find the dimensions of the rectangle meeting the specified condition. ​
The perimeter is 528 feet and the length is $$4 \frac { 1 } { 2 }$$ times the width.
​
A)216 ft × 52 ft
B)216 ft × 48 ft
C)220 ft × 52 ft
D)218 ft × 48 ft
E)218 ft × 50 ft

Quizplus · Accepted Answer

The perimeter of a rectangle is given by 2(length + width). Let the width be x, then the length is $4 \frac{1}{2}x = \frac{9}{2}x$. The equation becomes 2(x + $\frac{9}{2}x$) = 528. Solving for x gives x = 48 ft (width) and length = 216 ft.

Find the Dimensions of the Rectangle Meeting the Specified Condition 4124 \frac { 1 } { 2 }421​

Find the Dimensions of the Rectangle Meeting the Specified Condition $4 \frac { 1 } { 2 }$