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Question 12
Find 3A. A=[5−223−35]A = \left[ \begin{array} { c c } 5 & - 2 \\2 & 3 \\- 3 & 5\end{array} \right]A=52−3−235
A) [15−669−915]\left[ \begin{array} { c c } 15 & - 6 \\6 & 9 \\- 9 & 15\end{array} \right]156−9−6915 B) [17−6615−99]\left[ \begin{array} { c c } 17 & - 6 \\6 & 15 \\- 9 & 9\end{array} \right]176−9−6159 C) [19−6−99615]\left[ \begin{array} { c c } 19 & - 6 \\- 9 & 9 \\6 & 15\end{array} \right]19−96−6915 D) [1396−6−915]\left[ \begin{array} { c c } 13 & 9 \\6 & - 6 \\- 9 & 15\end{array} \right]136−99−615 E) [11−696−915]\left[ \begin{array} { c c } 11 & - 6 \\9 & 6 \\- 9 & 15\end{array} \right]119−9−6615
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