Solve the system of linear equations. $$\left\{ \begin{array} { c }
x - 2 y = 6 \
2 x - 3 y = 4
\end{array} \right.$$
A) $( - 10 , - 8 )$
B) $( - 10,8 )$
C) $( - 10,4 )$
D) $( - 4 , - 10 )$
E) $( 10,8 )$

Question

Solve the system of linear equations.​ $$\left\{ \begin{array} { c } 
x - 2 y = 6 \
2 x - 3 y = 4
\end{array} \right.$$ ​ ​
A)​ $( - 10 , - 8 )$
B)​ $( - 10,8 )$
C)​ $( - 10,4 )$
D)​ $( - 4 , - 10 )$
E)​ $( 10,8 )$

Quizplus · Accepted Answer

Explanation:Multiply the first equation by -2 and add it to the second equation to get:-7y = -8y = 8/7Substitute y = 8/7 into the first equation to get:x - 2(8/7) = 6x = 6 + 16/7x = 56/7Therefore, the solution to the system of equations is (56/7, 8/7).

Solve the System of Linear Equations {x−2y=62x−3y=4\left\{ \begin{array} { c } x - 2 y = 6 \\2 x - 3 y = 4\end{array} \right.{x−2y=62x−3y=4​

Solve the System of Linear Equations $\left\{ \begin{array} { c } x - 2 y = 6 \\2 x - 3 y = 4\end{array} \right.$