Select the first five terms of the sequence.(Assume that n begins with 1. ) $$a _ { n } = \frac { n + 11 } { n }$$
A) $11,12 , \frac { 13 } { 2 } , \frac { 14 } { 3 } , \frac { 15 } { 4 }$
B) $- 12 , \frac { 13 } { 2 } , - \frac { 14 } { 3 } , \frac { 15 } { 4 } , - \frac { 16 } { 5 }$
C) $12 , - \frac { 13 } { 2 } , - \frac { 14 } { 3 } , - \frac { 15 } { 4 } , - \frac { 16 } { 5 }$
D) $12 , \frac { 13 } { 2 } , \frac { 14 } { 3 } , \frac { 15 } { 4 } , \frac { 16 } { 5 }$
E) $\frac { 1 } { 12 } , \frac { 1 } { 13 } , \frac { 1 } { 14 } , \frac { 1 } { 15 } , \frac { 1 } { 16 }$

Question

Select the first five terms of the sequence.(Assume that n begins with 1. )​ $$a _ { n } = \frac { n + 11 } { n }$$ ​
A) $11,12 , \frac { 13 } { 2 } , \frac { 14 } { 3 } , \frac { 15 } { 4 }$
B) $- 12 , \frac { 13 } { 2 } , - \frac { 14 } { 3 } , \frac { 15 } { 4 } , - \frac { 16 } { 5 }$
C) $12 , - \frac { 13 } { 2 } , - \frac { 14 } { 3 } , - \frac { 15 } { 4 } , - \frac { 16 } { 5 }$
D) $12 , \frac { 13 } { 2 } , \frac { 14 } { 3 } , \frac { 15 } { 4 } , \frac { 16 } { 5 }$
E) $\frac { 1 } { 12 } , \frac { 1 } { 13 } , \frac { 1 } { 14 } , \frac { 1 } { 15 } , \frac { 1 } { 16 }$

Quizplus · Accepted Answer

The sequence is defined as $a_n = \frac{n + 11}{n}$. Calculating the first five terms:  For $n=1$, $a_1 = \frac{1+11}{1} = 12$.  For $n=2$, $a_2 = \frac{2+11}{2} = \frac{13}{2}$.  For $n=3$, $a_3 = \frac{3+11}{3} = \frac{14}{3}$.  For $n=4$, $a_4 = \frac{4+11}{4} = \frac{15}{4}$.  For $n=5$, $a_5 = \frac{5+11}{5} = \frac{16}{5}$.  Thus, the correct sequence is option D.

Select the First Five Terms of the Sequence an=n+11na _ { n } = \frac { n + 11 } { n }an​=nn+11​

Select the First Five Terms of the Sequence $a _ { n } = \frac { n + 11 } { n }$