A force acting on an object moving along the x axis is given by F_x = (14x-3.0x²)N where x is in m.How much work is done by this force as the object moves from x = -1 m to x = +2 m? A)+12 J B)+28 J C)+40 J D)+42 J E)-28 J

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Quizplus · Accepted Answer

The work done by a force is given by the integral of the force with respect to displacement. In this case, the force is given by F_x = (14x - 3.0x²)N and the displacement is from x = 1 m to x = 2 m. Therefore, the work done is:$$W = \int_{1}^{2} (14x - 3.0x^2)dx = [7x^2 - x^3]_1^2 = 12 J$$

A Force Acting on an Object Moving Along the X