f(x) = $x ^ { 5 }$ + x - 3 has a zero between 1 and 2 .
Use two repetitions of the Newton-Raphson algorithm to approximate this zero with $x _ { 0 } = 1$ Enter just a real number rounded off to two decimal places.

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The Answer of f(x) = $x ^ { 5 }$ + x - 3 has a zero between 1 and 2 .
Use two repetitions of the Newton-Raphson algorithm to approximate this zero with $x _ { 0 } = 1$ Enter just a real number rounded off to two decimal places.

F(x) = x5x ^ { 5 }x5 + X - 3 Has a Zero Between 1 and 3

F(x) = $x ^ { 5 }$ + X - 3 Has a Zero Between 1 and 3