f(x) = $e ^ { x }$ + $\mathrm { e } ^ { 2 x }$ + $\frac { 1 } { e ^ { - 4 x } }$ Enter your answer exactly as just P( $e ^ { x }$ ) where P is a polynomial in $e ^ { x }$ in standard form.

Question

Quizplus · Accepted Answer

The Answer of f(x) = $e ^ { x }$ + $\mathrm { e } ^ { 2 x }$ + $\frac { 1 } { e ^ { - 4 x } }$ Enter your answer exactly as just P( $e ^ { x }$ ) where P is a polynomial in $e ^ { x }$ in standard form.

F(x) = exe ^ { x }ex e2x\mathrm { e } ^ { 2 x }e2x

F(x) = $e ^ { x }$ $\mathrm { e } ^ { 2 x }$