Determine the domain and the range. $F ( x ) = \frac { x ^ { 3 } + 6 } { x ^ { 3 } - 2 }$
A) domain: $( - \infty , \sqrt [ 3 ] { 2 } ) \cup ( \sqrt [ 3 ] { 2 } , \infty )$ ; range: $( - \infty , \infty )$
B) domain: $( - \infty , \sqrt [ 3 ] { 2 } ) \cup ( \sqrt [ 3 ] { 2 } , \infty )$ ; range: $( - \infty , 1 ) \cup ( 1 , \infty )$
C) domain: $\left( - \infty , 2 ^ { 3 } \right) \cup \left( 2 ^ { 3 } , \infty \right)$ ; range: $( - \infty , 1 ) \cup ( 1 , \infty )$
D) domain: $( - \infty , - \sqrt [ 3 ] { 2 } ) \cup ( - \sqrt [ 3 ] { 2 } , \infty )$ ; range: $( - \infty , \infty )$
E) domain: $( - \infty , \sqrt [ 3 ] { 2 } ) \cup ( \sqrt [ 3 ] { 2 } , \infty )$ ; range: $( - \infty , 0 ) \cup ( 0 , \infty )$

Question

Quizplus · Accepted Answer

The Answer is B

Determine the Domain and the Range F(x)=x3+6x3−2F ( x ) = \frac { x ^ { 3 } + 6 } { x ^ { 3 } - 2 }F(x)=x3−2x3+6​

Determine the Domain and the Range $F ( x ) = \frac { x ^ { 3 } + 6 } { x ^ { 3 } - 2 }$