What is the specific activity (in Ci/g) of an isotope if 3.56 mg emits 4.26 × 10⁸ $\beta$ particles per second? A) 0.003232 Ci/g B) 0.0115 Ci/g C) 0.309 Ci/g D) 3.23 Ci/g E) none of the above

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Quizplus · Accepted Answer

Specific activity is calculated by dividing the decay rate by the mass of the isotope. Here, (4.26 × 10^8 particles/s) / (3.56 mg) = 1.197 × 10^11 particles/s/g. Converting to Ci (1 Ci = 3.7 × 10^10 particles/s), the specific activity is approximately 3.23 Ci/g.

What Is the Specific Activity (In Ci/g) of an Isotope β\betaβ

What Is the Specific Activity (In Ci/g) of an Isotope $\beta$