Lead(II) iodide, PbI₂, is an ionic compound with a solubility product constant
K_sp of 7.9 × 10^-9.Calculate the solubility of this compound in
a. pure water.
b. 0.50 mol L^-1 KI solution.

Question

Lead(II) iodide, PbI₂, is an ionic compound with a solubility product constant K_sp of 7.9 × 10^-9.Calculate the solubility of this compound in a. pure water. b. 0.50 mol L^-1 KI solution.

Quizplus · Accepted Answer

The Answer of Lead(II) iodide, PbI₂, is an ionic compound with a solubility product constant K_sp of 7.9 × 10^-9.Calculate the solubility of this compound in a. pure water. b. 0.50 mol L^-1 KI solution.

Lead(II) Iodide, PbI2, Is an Ionic Compound with a Solubility

Lead(II) Iodide, PbI₂, Is an Ionic Compound with a Solubility