How many grams of oxygen are needed to react completely with 200.0 g of ammonia, NH₃? 4NH₃(g) + 5O₂(g) $\to$ 4NO(g) + 6H₂O(g) A) 469.7 g B) 300.6 g C) 250.0 g D) 3.406 g E) 2.180 g

Question

Quizplus · Accepted Answer

To find the grams of oxygen needed, first calculate the moles of NH3 in 200.0 g (200.0 g / 17.03 g/mol = 11.75 mol). According to the balanced equation, 5 moles of O2 are needed for every 4 moles of NH3. Therefore, (11.75 mol NH3) * (5 mol O2 / 4 mol NH3) = 14.69 mol O2. Finally, convert moles of O2 to grams (14.69 mol * 32.00 g/mol = 469.7 g).

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