Consider the following code snippet. What does the array contain at the end of the program?
Public static fillWithRandomNumbers(double[] values)
{
Double[] numbers = new double[values.length];
For (int i = 0; i

Question

Consider the following code snippet. What does the array contain at the end of the program?
Public static fillWithRandomNumbers(double[] values)
{
Double[] numbers = new double[values.length];
For (int i = 0; i < numbers.length; i++)
{
Numbers[i] = Math.random();
}
Values = numbers;
}
Public static void main(String[] args)
{
Double[] num = new double[20];
FillWithRandomNumbers(num);
}
A) 20 random numbers
B) Undefined data due to compilation error
C) 20 zeros because array num is not changed by method
D) Array index bound error

Quizplus · Accepted Answer

The code snippet creates an array of 20 doubles named "num" and passes it to the "fillWithRandomNumbers" method. Inside the method, the code creates a new array named "numbers" of the same length as "values" (which is "num"). Then, it uses a loop to fill "numbers" with random double values. Finally, the method assigns the "numbers" array to the "values" parameter, which is a reference to the "num" array in the main method. Therefore, when the method returns, the "num" array in the main method should contain the same random values as the "numbers" array created inside the method. Thus, the array contains 20 random numbers.

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