Given the Following Reduction Potentials,
NAD⁺ + H⁺ + 2e^- $\to$

Given the following reduction potentials,
NAD⁺ + H⁺ + 2e^- $\to$ NADH $~~~~~~~~$ E ^$\circ$ = -0.105 V
2H⁺ + 2e^- $\to$ H₂ $~~~~~~~~$$~~~~~~~~$$~~~~~~~~$ E ^$\circ$ = 0.000 V

Calculate the standard reduction potential and identify the reducing agent in the following reaction.
NAD⁺ + H₂ $\to$ NADH + 2H⁺

A) 0.105 V,NAD⁺
B) -0.105 V,NAD⁺
C) -0.105 V,H₂
D) 0.105 V,H₂
E) -0.105 V,NADH