Use the Standard Reduction Potentials Below to Determine Which Element $\to$

Use the standard reduction potentials below to determine which element or ion is the best oxidizing agent.
O₂(g) + 4 H⁺(aq) + 4 e^- $\to$ 2 H₂O( ) $~~~~~~~~$$~~~~~~~~$ E ^$\circ$ = +1.229 V
Hg₂²⁺(aq) + 2 e^- $\to$ 2 Hg( ) $~~~~~~~~$$~~~~~~~~$$~~ ~ ~~~$$~ ~~~$ E ^$\circ$ = +0.789 V
I₂(s) + 2 e^- $\to$ 2 I^-(aq) $~~~~~~~~$$~~ ~~~~$$~~~~~~~~$$~~~~~~~~$$~~ ~~~~~$ E ^$\circ$ = +0.535 V

A) I₂(s)
B) O₂(g)
C) I^-(aq)
D) Hg₂²⁺(aq)
E) H₂O( )