Using the following thermochemical equation,determine the amount of heat produced from the combustion of 48.6 g benzene (C₆H₆).The molar mass of benzene is 78.11 g/mole. 2 C₆H₆(l)+ 15 O₂(g)→ 12 CO₂(g)+ 6 H₂O(g)ΔH°_rxn= -6278 kJ A) 7820 kJ B) 3900 kJ C) 1950 kJ D) 80.2 kJ E) 0.604 kJ

Question

Quizplus · Accepted Answer

The combustion of 48.6 g of benzene corresponds to 48.6 g / 78.11 g/mol = 0.622 moles of benzene. The given reaction shows that 2 moles of benzene release -6278 kJ. Therefore, 0.622 moles will release (0.622 / 2) * -6278 kJ = -1950 kJ.

Using the Following Thermochemical Equation,determine the Amount of Heat Produced