Use the ΔH°_f and ΔH°_rxninformation provided to calculate ΔH°_f for SO₃(g) : ΔH°_{f (kJ/mol)} 2 SO₂(g) + O₂(g) → 2 SO₃(g) ΔH°_rxn= -198 kJ
SO₂(g) -297

Question

Quizplus · Accepted Answer

The reaction is 2 SO₂(g) + O₂(g) → 2 SO₃(g) with ΔH°ₓₙ = -198 kJ. Using ΔH°ₓₙ = ΣΔH°f(products) - ΣΔH°f(reactants), we have: -198 kJ = [2ΔH°f(SO₃)] - [2(-297 kJ)]. Solving for ΔH°f(SO₃), we get ΔH°f(SO₃) = -396 kJ/mol.

Use the ΔH°f and ΔH°rxn information Provided to Calculate ΔH°f

Use the ΔH°_f and ΔH°_rxninformation Provided to Calculate ΔH°_f