A mixture of 0.220 moles Rn,0.350 moles O₂ and 0.640 moles Ar has a total pressure of 2.95 atm.What is the partial pressure of O₂? A) 1.17 atm B) 0.853 atm C) 1.03 atm D) 0.969 atm E) 0.649 atm

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Quizplus · Accepted Answer

To find the partial pressure of O₂, we need to use the mole fraction of O₂ in the mixture. First, we need to find the total moles of gas in the mixture: Total moles of gas = 0.220 moles Rn + 0.350 moles O₂ + 0.640 moles Ar = 1.21 moles Next, we can calculate the mole fraction of O₂: Mole fraction of O₂ = (0.350 moles O₂) / (1.21 moles) Mole fraction of O₂ = 0.289 Finally, we can use the mole fraction to calculate the partial pressure of O₂: Partial pressure of O₂ = Mole fraction of O₂ × Total pressure Partial pressure of O₂ = 0.289 × 2.95 atm Partial pressure of O₂ = 0.853 atm Therefore, the answer is B) 0.853 atm.

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