Instruction 9-7
Microsoft Excel was used on a set of data involving the number of parasites found in a random sample of 46 Blue Tiger butterflies captured in Kakadu National Park. A biologist wants to know if the mean number of parasites per butterfly is greater than 20. She will make her decision using a test with a level of significance of 0.10. The following information was extracted from the Microsoft Excel output for the sample of 46 butterflies:
$n = 46$; Arithmetic Mean $= 28.00$; Standard Deviation $= 25.92$; Standard Error $= 3.82$;
Null Hypothesis: $H _ { 0 } : \mu \leq 20.000 ; a = 0.10 ; \mathrm { df } = 45 ; T$ Test Statistic $= 2.09$;
One-Tailed Test Upper CriticalValue $= 1.3006 ; p$ value $= 0.021$; Decision $=$ Reject.
-Referring to Instruction 9-7,the null hypothesis would be rejected.

Question

Instruction 9-7
Microsoft Excel was used on a set of data involving the number of parasites found in a random sample of 46 Blue Tiger butterflies captured in Kakadu National Park. A biologist wants to know if the mean number of parasites per butterfly is greater than 20. She will make her decision using a test with a level of significance of 0.10. The following information was extracted from the Microsoft Excel output for the sample of 46 butterflies:
 $n = 46$; Arithmetic Mean $= 28.00$; Standard Deviation $= 25.92$; Standard Error $= 3.82$;
Null Hypothesis: $H _ { 0 } : \mu \leq 20.000 ; a = 0.10 ; \mathrm { df } = 45 ; T$ Test Statistic $= 2.09$;
One-Tailed Test Upper CriticalValue $= 1.3006 ; p$ value $= 0.021$; Decision $=$ Reject.
-Referring to Instruction 9-7,the null hypothesis would be rejected.

Quizplus · Accepted Answer

The Microsoft Excel output for the sample does not provide the necessary information to determine whether the null hypothesis should be rejected or not. Therefore, the answer to this question cannot be determined from the given information.

Instruction 9-7 Microsoft Excel Was Used on a Set n=46n = 46n=46

Instruction 9-7
Microsoft Excel Was Used on a Set $n = 46$