If the z-value for a given value x of the random variable x is z = 1.96,and the distribution of x is normally distributed with a mean of 60 and a standard deviation of 6,then the x-value that this z-value corresponds to is:
A) 71.76.
B) 67.96.
C) 61.96.
D) 48.24.

Question

Quizplus · Accepted Answer

The z-score formula is z = (x - μ) / σ, where x is the value, μ is the mean, and σ is the standard deviation. Plugging in the values: 1.96 = (x - 60) / 6. Solving for x gives x = 1.96 * 6 + 60 = 11.76 + 60 = 71.76.

If the Z-Value for a Given Value X of the Random