A resistor,inductor and capacitor are connected in series,each with effective (rms)voltage of 80.0 V,160 V,and 84.0 V,respectively.If the resistor is rated at 15.0 Ω,what is the average power dissipated in the circuit?
A)812 W
B)427 W
C)309 W
D)589 W
E)559 W

Question

Quizplus · Accepted Answer

The average power dissipated in a series RLC circuit is given by $P = \frac{V_{R}^2}{R}$, where $V_{R}$ is the voltage across the resistor and $R$ is the resistance. Given $V_{R} = 80.0 \, \text{V}$ and $R = 15.0 \, \Omega$, the power is $P = \frac{80.0^2}{15.0} = \frac{6400}{15.0} = 426.67 \, \text{W}$, which rounds to $427 \, \text{W}$.

A Resistor,inductor and Capacitor Are Connected in Series,each with Effective