An electron is accelerated from rest through 2300 V and then enters a region of uniform magnetic field with magnitude 1.25 T.What is the magnitude of the maximum magnetic force acting on the electron?
A)5.68E-12 N
B)4.02E-12 N
C)4.07E-12 N
D)2.03E-12 N

Question

​An electron is accelerated from rest through 2300 V and then enters a region of uniform magnetic field with magnitude 1.25 T.What is the magnitude of the maximum magnetic force acting on the electron?
A)​5.68E-12 N
B)​4.02E-12 N
C)​4.07E-12 N
D)​2.03E-12 N

Quizplus · Accepted Answer

The maximum magnetic force on a charged particle is given by F = qvB, where q is the charge of the particle, v is its velocity, and B is the magnetic field strength. In this case, the electron has a charge of -1.602 x 10^-19 C, and its velocity is given by v = sqrt(2eV/m), where e is the electron's charge, V is the accelerating voltage, and m is the electron's mass. Plugging in the given values, we get v = 1.87 x 10^7 m/s. The magnetic field strength is given as 1.25 T. Plugging in these values, we get F = (-1.602 x 10^-19 C)(1.87 x 10^7 m/s)(1.25 T) = -4.07 x 10^-12 N. The negative sign indicates that the force is in the opposite direction of the electron's motion.

​An Electron Is Accelerated from Rest Through 2300 V and Then

An Electron Is Accelerated from Rest Through 2300 V and Then