A horizontal force of 850 N is needed to overcome the force of static friction between a level floor and a 350-kg crate.If g = 9.8 m/s²,what is the coefficient of static friction? A)24.8 B)2.48 C)4.04 D)0.248 E)2.43

Question

Quizplus · Accepted Answer

The equation for static friction is:

f_s = μ_s N

where f_s is the force of static friction, μ_s is the coefficient of static friction, and N is the normal force (equal in magnitude to the force of gravity).

In this problem, the force of static friction is given as 850 N and the mass of the crate is 350 kg.

The normal force can be found using:

N = m*g

N = 350 kg * 9.8 m/s^2

N = 3430 N

Substituting these values into the equation for static friction, we get:

850 N = μ_s * 3430 N

μ_s = 850 N / 3430 N

μ_s = 0.248

Therefore, the coefficient of static friction is 0.248, which corresponds to choice D.

A Horizontal Force of 850 N Is Needed to Overcome