Two blocks in contact with each other are pushed to the right across a rough horizontal surface by the two forces shown.If the coefficient of kinetic friction between each of the blocks and the surface is 0.30,determine the magnitude of the force exerted on the 2.0-kg block by the 3.0-kg block.
A)15 N
B)25 N
C)11 N
D)22 N
E)33 N

Question

Two blocks in contact with each other are pushed to the right across a rough horizontal surface by the two forces shown.If the coefficient of kinetic friction between each of the blocks and the surface is 0.30,determine the magnitude of the force exerted on the 2.0-kg block by the 3.0-kg block. 
A)15 N 
B)25 N 
C)11 N 
D)22 N 
E)33 N

Quizplus · Accepted Answer

First, we need to find the net force acting on the system. To do this, we can subtract the force of friction from the applied force. 
For the 3.0 kg block: 
F_applied - F_friction = 15 N - (0.30)(3.0 kg)(9.8 m/s^2) = 4.86 N
For the 2.0 kg block: 
F_friction = (0.30)(2.0 kg)(9.8 m/s^2) = 5.88 N
Therefore, the net force acting on the 2.0 kg block is: 
F_net = F_block3 - F_friction = 15 N - 5.88 N = 9.12 N
Thus, the magnitude of the force exerted on the 2.0 kg block by the 3.0 kg block is 9.12 N.

Two Blocks in Contact with Each Other Are Pushed to the Right