How many mL of a 4.50 (m/v)% solution would contain 23.0 g of solute?
A)19.6 mL
B)511 mL
C)1.04 mL
D)10.35 mL

Question

How many mL of a 4.50 (m/v)% solution would contain 23.0 g of solute?
A)19.6 mL 
B)511 mL 
C)1.04 mL 
D)10.35 mL

Quizplus · Accepted Answer

We can use the formula:
m = (m/v) x V
where m is the mass of solute (23.0 g), (m/v) is the concentration (4.50%), and V is the volume of solution we need to find. Rearranging the formula, we get:
V = m / (m/v)
Substituting the values, we get:
V = 23.0 g / (4.50 g/100 mL)
V = 511 mL
Therefore, the answer is B, 511 mL.

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