What is the empirical formula of a substance that consists of 3.704g aluminum and 3.295g oxygen? A)AlO B)AlO₂ C)Al₂O₃ D)Al₃O₂

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Quizplus · Accepted Answer

To find the empirical formula, convert the masses to moles: Al: 3.704g / 26.98g/mol = 0.1372 mol, O: 3.295g / 16.00g/mol = 0.2059 mol. Divide by the smallest number of moles: Al: 0.1372/0.1372 = 1, O: 0.2059/0.1372 ≈ 1.5. Multiply by 2 to get whole numbers: Al: 2, O: 3. Thus, the empirical formula is Al₂O₃.

What Is the Empirical Formula of a Substance That Consists