How many grams of iron (density = 7.87 g/mL )would occupy the same volume as 96.4 g of aluminum (density = 2.70 g/mL)?
A)4.54 g
B)33.1 g
C)281 g
D)220.g

Question

Quizplus · Accepted Answer

First, we need to find the volume of the 96.4 g aluminum.

density of aluminum = mass/volume 
volume = mass/density = 96.4 g / 2.70 g/mL = 35.70 mL

Next, we can use the volume of aluminum to find the mass of iron that would occupy the same volume.

density of iron = mass/volume 
mass = density x volume = 7.87 g/mL x 35.70 mL = 280.8 g

Therefore, 280.8 g of iron would occupy the same volume as 96.4 g of aluminum. However, we need to round the answer to one significant figure, giving a final answer of 281 g.

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