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A large circular target 6 ft in diameter is laid flat on the ground with the bulls-eye exactly 386 feet away from the archers. An archer shoots an arrow at an angle of 35° above the horizontal with an initial velocity of 115 feet per second. (Assume the arrow is shot from ground level).
-Does the arrow hit the target?
A) No
B) Yes

Question

Quizplus · Accepted Answer

The arrow's range can be calculated using the formula $R = \frac{v^2 \sin 2\theta}{g}$, where $v$ is the initial velocity, $\theta$ is the angle of projection, and $g$ is the acceleration due to gravity (approximately $32.2 \text{ ft/s}^2$). Plugging in the given values, $R = \frac{(115)^2 \sin(70)}{32.2}$ results in a range less than 386 feet, indicating the arrow does not hit the target.

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