0.400 g of solid NaCl is added to 50 mL of a 0.100 M MgCl₂ solution.Assuming the final volume does not change,what is the molarity of chloride ion in the final solution? A)0.237 B)0.108 C)0.208 D)0.337 E)0.137

Question

Quizplus · Accepted Answer

The moles of Cl⁻ from MgCl₂ are 0.100 M * 0.050 L * 2 = 0.010 moles. The moles of Cl⁻ from NaCl are 0.400 g / 58.44 g/mol = 0.00685 moles. Total moles of Cl⁻ = 0.010 + 0.00685 = 0.01685 moles. Molarity = 0.01685 moles / 0.050 L = 0.337 M.

0400 G of Solid NaCl Is Added to 50 ML