How many grams of CH₃OH must be added to water to prepare 150 mL of a solution that is 2.0 M CH₃OH? A)0.0096 B)430 C)2.4 D)9.6 E)4.3

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Quizplus · Accepted Answer

The molar mass of CH₃OH is 88.13 g/mol. To prepare a 2.0 M solution, we need to add: (2.0 mol/L) x (0.150 L) x (88.13 g/mol) = 26.439 g Therefore, we need to add 26.439 g of CH₃OH to prepare 150 mL of a 2.0 M solution. This corresponds to 9.6 g rounded to one decimal place, so the answer is D) 9.6.

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