How many moles of K⁺ are present in 343 mL of a 1.27 M solution of K₃PO₄? A)0.436 B)1.31 C)0.145 D)3.70 E)11.1

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Quizplus · Accepted Answer

The molarity (M) of the solution is 1.27 M, meaning there are 1.27 moles of K₃PO₄ per liter. In 343 mL (0.343 L), there are 0.343 L * 1.27 mol/L = 0.436 moles of K₃PO₄. Each K₃PO₄ contains 3 moles of K⁺, so there are 0.436 moles * 3 = 1.31 moles of K⁺.

How Many Moles of K+ Are Present in 343 ML

How Many Moles of K⁺ Are Present in 343 ML