Consider the reaction 2N₂O₅(g)$\rightarrow$ 4NO₂(g)+ O₂(g) Rate = k[N₂O₅] If the initial concentration of N₂O₅ is 0.80 M,The concentration after 5 half-lives is A) 0.11 M. B) 0.025 M. C) 0.032 M. D) 0.16 M. E) 0.050 M.

Question

Quizplus · Accepted Answer

After every half-life, the concentration of the reactant will be halved. Hence, after 5 half-lives, the concentration will be reduced to (1/2)^5 = 1/32 times its initial value. Therefore, [N₂O₅] = 0.80 M x 1/32 = 0.025 M. Therefore, the correct answer is option B.

Consider the Reaction 2N2O5(g) →\rightarrow→ 4NO2(g)+ O2(g) Rate = K[N2O5] If the Initial Concentration of

Consider the Reaction
2N₂O₅(g) $\rightarrow$ 4NO₂(g)+ O₂(g)
Rate = K[N₂O₅]
If the Initial Concentration of