Calculate the standard entropy of fusion of ethanol at its melting point, 159 K. The standard molar enthalpy of fusion of ethanol at its melting point is 5.02 kJ.mol^-¹. A) -5.02 kJ.K^-¹.mol^-¹ B) -31.6 J.K^-¹.mol^-¹ C) +5.02 J.K^-¹.mol^-¹ D) +31.6 J.K^-¹.mol^-¹ E) -44.0 J.K^-¹.mol^-¹

Question

Quizplus · Accepted Answer

The standard entropy of fusion ($\Delta S_{fus}$) can be calculated using the formula $\Delta S_{fus} = \frac{\Delta H_{fus}}{T}$, where $\Delta H_{fus}$ is the enthalpy of fusion and $T$ is the temperature in Kelvin. Given $\Delta H_{fus} = 5.02 \, \text{kJ/mol}$ and $T = 159 \, \text{K}$, converting $\Delta H_{fus}$ to J/mol gives $5020 \, \text{J/mol}$. Thus, $\Delta S_{fus} = \frac{5020 \, \text{J/mol}}{159 \, \text{K}} \approx 31.6 \, \text{J/mol}\cdot\text{K}$.

Calculate the Standard Entropy of Fusion of Ethanol at Its