When a 0.20-kg block is suspended from a vertically hanging spring, it stretches the spring from its original length of 0.040 m to 0.045 m. The same block is attached to the same spring and placed on a horizontal, frictionless surface as shown. The block is then pulled so that the spring stretches to a total length of 0.15 m. The block is released at time t = 0 s and undergoes simple harmonic motion.
-What is the total mechanical energy of the system at any instant?
A)0.25 J
B)0.49 J
C)0.98 J
D)4.4 J
E)9.8 J

Question

When a 0.20-kg block is suspended from a vertically hanging spring, it stretches the spring from its original length of 0.040 m to 0.045 m. The same block is attached to the same spring and placed on a horizontal, frictionless surface as shown. The block is then pulled so that the spring stretches to a total length of 0.15 m. The block is released at time t = 0 s and undergoes simple harmonic motion. 
-What is the total mechanical energy of the system at any instant?
A)0.25 J 
B)0.49 J 
C)0.98 J 
D)4.4 J 
E)9.8 J

Quizplus · Accepted Answer

The Answer of When a 0.20-kg block is suspended from a vertically hanging spring, it stretches the spring from its original length of 0.040 m to 0.045 m. The same block is attached to the same spring and placed on a horizontal, frictionless surface as shown. The block is then pulled so that the spring stretches to a total length of 0.15 m. The block is released at time t = 0 s and undergoes simple harmonic motion. 
-What is the total mechanical energy of the system at any instant?
A)0.25 J 
B)0.49 J 
C)0.98 J 
D)4.4 J 
E)9.8 J

When a 020-Kg Block Is Suspended from a Vertically Hanging Spring, It