Assuming a filament in a 100 W light bulb acts like a perfect blackbody, what is the temperature of the hottest portion of the filament if it has a surface area of 6.3 × 10^-⁵ m²? The Stefan-Boltzmann constant is 5.67 × 10^-⁸ W/(m² · K²). A)130 K B)1100 K C)2300 K D)5800 K E)30 000 K

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Quizplus · Accepted Answer

Using the Stefan-Boltzmann law, P = σAeT^4, where P is power, σ is the Stefan-Boltzmann constant, A is area, and T is temperature. Solving for T gives approximately 2300 K.

Assuming a Filament in a 100 W Light Bulb Acts