The figure shows a circuit. The switch S can be closed on either point A or C, but not both at the same time. Use the following quantities: V 1 = V 2 = 12 V R 1 = R 4 = 1.0 $\varOmega$ R 2 = R 3 = 2.0 $\varOmega$ -Determine the current through R₄ when the switch S is closed on C. A)zero amperes B)2 A C)3 A D)6 A E)24 A

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When the switch is closed, the capacitor will discharge through R4. The current through R4 will be equal to the current through the capacitor, which is given by:$$I = C\frac{dV}{dt}$$where:* I is the current in amperes* C is the capacitance in farads* V is the voltage across the capacitor in volts* t is the time in secondsIn this case, the capacitance is 100 μF, the voltage across the capacitor is 12 V, and the time is 0 seconds. Therefore, the current through R4 is:$$I = 100 \mu F 	imes \frac{12 V}{0 s} = 1200 A$$However, the maximum current that can flow through R4 is limited by the resistance of the resistor. In this case, the resistance of R4 is 2 ohms. Therefore, the current through R4 will be:$$I = \frac{V}{R} = \frac{12 V}{2 \Omega} = 6 A$$

The Figure Shows a Circuit Ω\varOmegaΩ R2 = R3 = 2 Ω\varOmegaΩ

The Figure Shows a Circuit $\varOmega$ R₂ = R₃ = 2 $\varOmega$