How many mL of 0.241 M H₂SO₄ will be needed to neutralize a 50.0 mL sample of 0.191 M KOH? A)19.8 mL B)31.5 mL C)39.6 mL D)79.3 mL E)126 mL

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Quizplus · Accepted Answer

To neutralize the KOH, we need an equal number of moles of H₂SO₄. The number of moles of KOH is:```moles KOH = (0.191 M) x (50.0 mL) = 9.55 mmol```Since H₂SO₄ has two acidic protons, we need half as many moles of H₂SO₄:```moles H₂SO₄ = 9.55 mmol / 2 = 4.775 mmol```The volume of 0.241 M H₂SO₄ needed to provide this number of moles is:```volume H₂SO₄ = (4.775 mmol) / (0.241 M) = 19.8 mL```Therefore, the correct answer is A) 19.8 mL.

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