A 50.0 mL sample of a 6.0 M solution of HCl is diluted to 200.mL.What is the new concentration?
A)24.0 M
B)6.0 M
C)2.10 M
D)2.00 M
E)1.50 M

Question

Quizplus · Accepted Answer

The new concentration after dilution can be calculated using the formula $C_1V_1 = C_2V_2$, where $C_1$ and $C_2$ are the initial and final concentrations, and $V_1$ and $V_2$ are the initial and final volumes. Substituting the given values: $6.0\, \text{M} \times 50.0\, \text{mL} = C_2 \times 200.0\, \text{mL}$. Solving for $C_2$ gives $C_2 = 1.5\, \text{M}$.

A 500 ML Sample of a 6