The partial pressures of CH₄,N₂,and O₂ in a sample of gas were found to be 143 mmHg,469 mmHg,and 251 mmHg,respectively.Calculate the mole fraction of oxygen. A)0.410 B)0.291 C)2.44 D)22.4

Question

Quizplus · Accepted Answer

To find the mole fraction of oxygen, we need to first calculate the total pressure of the gas sample by adding the partial pressures of all the gases:

Total pressure = 143 mmHg + 469 mmHg + 251 mmHg = 863 mmHg

Next, we need to find the mole fraction of oxygen (O2):

Mole fraction of O2 = Partial pressure of O2 / Total pressure

We are given the partial pressure of O2 as 251 mmHg, so:

Mole fraction of O2 = 251 mmHg / 863 mmHg = 0.291

Therefore, the answer is B.

The Partial Pressures of CH4,N2,and O2 in a Sample of Gas

The Partial Pressures of CH₄,N₂,and O₂ in a Sample of Gas