How many grams of XeF6 are required to react with 1.16 L of hydrogen gas at 2.46 atm and 45°C in the reaction shown below? XeF6(s) + 3 H2(g) → Xe(g) + 6 HF(g)
A) 7.30 g
B) 8.92 g
C) 26.8 g
D) 80.4 g
Correct Answer:
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