A molecule with the formula XF₃ where the element X has the hybridization sp³.Which of the following elements could be Y? A)C B)P C)B D)Si

Question

Quizplus · Accepted Answer

The hybridization sp^3 suggests that the element X forms four equivalent bonds, which is characteristic of elements in Group 14 of the periodic table. Among the options given, phosphorus (P) is the only element that does not belong to Group 14. Carbon (C), Boron (B), and Silicon (Si) are all in Group 14 and can exhibit sp^3 hybridization. However, the question seems to have a typographical error in referring to the element to be identified as both X and Y, and in the context provided, phosphorus (P) does not fit the criteria for sp^3 hybridization, which is typically associated with elements that can form four bonds, like carbon (C) and silicon (Si). Boron (B) typically forms three bonds due to its electron configuration and does not usually exhibit sp^3 hybridization. Given the confusion in the question's presentation, the explanation is based on the assumption that the element with sp^3 hybridization is being asked about, which would exclude phosphorus (P) based on its typical bonding and hybridization characteristics.

A Molecule with the Formula XF3 Where the Element X

A Molecule with the Formula XF₃ Where the Element X