What is the pOH of an aqueous solution at 25.0°C in which [H⁺] is 0.0025 M? A)8.01 B)11.40 C)-11.40 D)-8.01 E)none of the above

Question

Quizplus · Accepted Answer

First, we need to calculate the concentration of hydroxide ions: [OH-] = Kw /[H+] = 1.0 x 10^-14 / [H⁺] [H⁺] = 0.0025 M [OH-] = 1.0 x 10^-14 / 0.0025 = 4.0 x 10^-12 M Then, we can use the pOH equation: pOH = -log[OH-] = -log(4.0 x 10^-12) = 11.4 Finally, we can use the relationship between pH and pOH: pH + pOH = 14 pH = 14 - pOH = 14 - 11.4 = 2.6 So, the pOH of the solution at 25.0°C is 11.40 (Choice B).

What Is the POH of an Aqueous Solution at 25