A solution is prepared by dissolving 22.7 g of CaCl₂ in 375 g of water. The density of the resulting solution is 1.05 g/mL. The concentration of CaCl₂ is __________% by mass. A)5.71 B)5.99 C)0.0599 D)0.0571 E)6.24

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The correct answer is A.The concentration of CaCl2 is 5.71% by mass.Explanation:First, we need to calculate the mass of the solution:mass of solution = mass of CaCl2 + mass of watermass of solution = 22.7 g + 375 gmass of solution = 397.7 gNext, we need to calculate the volume of the solution:volume of solution = mass of solution / density of solutionvolume of solution = 397.7 g / 1.05 g/mLvolume of solution = 379.2 mLFinally, we can calculate the concentration of CaCl2:concentration of CaCl2 = (mass of CaCl2 / mass of solution) x 100%concentration of CaCl2 = (22.7 g / 397.7 g) x 100%concentration of CaCl2 = 5.71%

A Solution Is Prepared by Dissolving 22