Calculate the freezing point of a 0.05500 m aqueous solution of NaNO₃. The molal freezing-point-depression constant of water is 1.86 °C/m. A)0.0286 B)-0.106 C)0.106 D)-0.0562 E)-0.205

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The freezing point depression is calculated using ΔTf = i * Kf * m, where i is the van't Hoff factor (2 for NaNO3), Kf is the freezing-point-depression constant (1.86 °C/m), and m is the molality (0.05500 m). ΔTf = 2 * 1.86 * 0.05500 = 0.2052 °C. The freezing point of water is 0 °C, so the new freezing point is 0 - 0.2052 = -0.205 °C.

Calculate the Freezing Point of a 0