Calculate the molality of a 24.4% (by mass)aqueous solution of phosphoric acid (H₃PO₄). A)3.29 m B)323 m C)6.59 m D)1.65 m E)The density of the solution is needed to solve the problem.

Question

Quizplus · Accepted Answer

To calculate the molality of the solution, we need to know the moles of solute (phosphoric acid) and the mass of solvent (water). 
Assuming 100 g of the solution: 
Mass of H3PO4 = 24.4 g 
Mass of H2O = 100 - 24.4 = 75.6 g

Now, we need to convert the mass of H3PO4 to moles: 
Molar mass of H3PO4 = 98 g/mol 
Moles of H3PO4 = 24.4 g / 98 g/mol = 0.249 moles

Molality = moles of solute / mass of solvent (in kg) 
Mass of solvent = 75.6 g = 0.0756 kg 
Molality = 0.249 moles / 0.0756 kg = 3.29 m

Therefore, the answer is A) 3.29 m

Calculate the Molality of a 24