A solution is prepared by dissolving 23.7 g of CaCl₂ in 375 g of water. The density of the resulting solution is 1.05 g/mL. The concentration of CaCl₂ in this solution is ________ molar. A)0.564 B)0.571 C)0.569 D)0.537 E)0.214

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Quizplus · Accepted Answer

The correct answer is A.The concentration of CaCl2 in the solution can be calculated using the formula:Concentration = (Mass of CaCl2 / Molar mass of CaCl2) / Volume of solutionThe molar mass of CaCl2 is 110.98 g/mol. The volume of the solution can be calculated using the density and mass of the solution:Volume = Mass / Density = 375 g / 1.05 g/mL = 357.14 mLSubstituting these values into the formula, we get:Concentration = (23.7 g / 110.98 g/mol) / 357.14 mL = 0.564 MTherefore, the concentration of CaCl2 in the solution is 0.564 M.

A Solution Is Prepared by Dissolving 23