The temperature of a 35.1 g sample of iron increases from 24.5 °C to 31.8 °C. If the specific heat of iron is 0.450 J/g-K, how many joules of heat are absorbed?
A)115 J
B)0.0936 J
C)-115 J
D)0.722 J
E)3.29 J

Question

Quizplus · Accepted Answer

We can use the formula Q = mcΔT, where Q is the amount of heat absorbed, m is the mass of the substance (in grams), c is the specific heat (in J/g-K), and ΔT is the change in temperature (in K or °C).

Substituting the given values, we get:

Q = (35.1 g)(0.450 J/g-K)(31.8 °C - 24.5 °C)
Q = (35.1 g)(0.450 J/g-K)(7.3 °C)
Q = 115 J

Therefore, the answer is A) 115 J, which represents the amount of heat absorbed by the iron sample.

The Temperature of a 35