Predict the direction in which the equilibrium will lie for the reaction C₆H₅COO^- + HF C₆H₅COOH + F^-.
K_a(C₆H₅COOH) = 6.5 *10^-5; K_a(HF) = 7.1 *10^-4

Question

Predict the direction in which the equilibrium will lie for the reaction C₆H₅COO^- + HF

Predict the direction in which the equilibrium will lie for the reaction C<sub>6</sub>H<sub>5</sub>COO<sup>-</sup> + HF C<sub>6</sub>H<sub>5</sub>COOH + F<sup>- </sup>. K<sub>a</sub>(C<sub>6</sub>H<sub>5</sub>COOH) = 6.5 *10<sup>-5</sup>; K<sub>a</sub>(HF) = 7.1 *10<sup>-4</sup> A) to the right B) to the left C) in the middle

C₆H₅COOH + F^-.
K_a(C₆H₅COOH) = 6.5 *10^-5; K_a(HF) = 7.1 *10^-4

Quizplus · Accepted Answer

Comparing the equilibrium constants, we can see that K for the forward reaction is larger than K for the reverse reaction. This indicates that at equilibrium, there will be a higher concentration of products (C₆H₅COOH + F^-) than reactants (C₆H₅COO^- + HF), meaning the equilibrium will lie to the right.

Predict the Direction in Which the Equilibrium Will Lie for the Reaction