What is the freezing point of an aqueous solution of a nonvolatile solute that has a boiling point of 102.5°C? For water K_f = 1.86°C/m and K_b = 0.52°C/m. A)-8.94°C B)-366°C C)-0.99°C D)0.99°C E)8.94°C

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We first need to find the molality of the solution using the boiling point elevation. deltaT = KB*m. Solving for m, we have m = deltaT/KB = (102.5-100)/0.52 = 4.81 molal. 
Next, we can use the molality to find the freezing point depression, deltaT = KF*m. Solving for deltaT, we have deltaT = KF*m = -1.86*4.81 = -8.94°C. Therefore, the freezing point of the solution is 0°C - 8.94°C = -8.94°C. The correct answer is (A).

What Is the Freezing Point of an Aqueous Solution of a Nonvolatile